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x/6=8x/x-5
We move all terms to the left:
x/6-(8x/x-5)=0
Domain of the equation: x-5)!=0We get rid of parentheses
x∈R
x/6-8x/x+5=0
We calculate fractions
x^2/6x+(-48x)/6x+5=0
We multiply all the terms by the denominator
x^2+(-48x)+5*6x=0
Wy multiply elements
x^2+(-48x)+30x=0
We get rid of parentheses
x^2-48x+30x=0
We add all the numbers together, and all the variables
x^2-18x=0
a = 1; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·1·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*1}=\frac{0}{2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*1}=\frac{36}{2} =18 $
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