13=1/5c+2

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Solution for 13=1/5c+2 equation: 



13=1/5c+2

We move all terms to the left:

13-(1/5c+2)=0



Domain of the equation: 5c+2)!=0

c∈R



We get rid of parentheses

-1/5c-2+13=0

We multiply all the terms by the denominator


-2*5c+13*5c-1=0

Wy multiply elements

-10c+65c-1=0

We add all the numbers together, and all the variables

55c-1=0

We move all terms containing c to the left, all other terms to the right

55c=1

c=1/55

c=1/55

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