x/4+x/5=(9x-4/(20)

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Solution for x/4+x/5=(9x-4/(20) equation: 



x/4+x/5=(9x-4/(20)

We move all terms to the left:

x/4+x/5-((9x-4/(20))=0

We add all the numbers together, and all the variables

x/4+x/5-((+9x-4/20)=0

We calculate fractions


200x^2/()+160x^2/()+(-((+9x-4*4*5)/()=0



We calculate terms in parentheses: +(-((+9x-4*4*5)/(), so:

-((+9x-4*4*5)/(

We add all the numbers together, and all the variables

-((9x-80)/(

We multiply all the terms by the denominator


-((9x-80)



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