2/6y+12=7/12y+2

Solution for 2/6y+12=7/12y+2 equation:

2/6y+12=7/12y+2

We move all terms to the left:

2/6y+12-(7/12y+2)=0


Domain of the equation: 6y!=0

y!=0/6

y!=0

y∈R



Domain of the equation: 12y+2)!=0

y∈R


We get rid of parentheses

2/6y-7/12y-2+12=0

We calculate fractions


24y/72y^2+(-42y)/72y^2-2+12=0

We add all the numbers together, and all the variables

24y/72y^2+(-42y)/72y^2+10=0

We multiply all the terms by the denominator


24y+(-42y)+10*72y^2=0

Wy multiply elements

720y^2+24y+(-42y)=0

We get rid of parentheses

720y^2+24y-42y=0

We add all the numbers together, and all the variables

720y^2-18y=0

a = 720; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·720·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*720}=\frac{0}{1440}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*720}=\frac{36}{1440}
=1/40
$