x/10=(1/9)(342-x)

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Solution for x/10=(1/9)(342-x) equation: 



x/10=(1/9)(342-x)

We move all terms to the left:

x/10-((1/9)(342-x))=0



Domain of the equation: 9)(342-x))!=0

x∈R



We add all the numbers together, and all the variables

x/10-((+1/9)(-1x+342))=0

We multiply parentheses ..

-((-1x^2+1/9*342))+x/10=0

We calculate fractions


(-((-1x^2+1*10)/()+9234x^2/()=0



We calculate terms in parentheses: +(-((-1x^2+1*10)/()+9234x^2/(), so:

-((-1x^2+1*10)/()+9234x^2/(

We can not solve this equation

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