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2(2x+3)+5(x+4)=4(2x+5)+8
We move all terms to the left:
2(2x+3)+5(x+4)-(4(2x+5)+8)=0
We multiply parentheses
4x+5x-(4(2x+5)+8)+6+20=0
We calculate terms in parentheses: -(4(2x+5)+8), so:We add all the numbers together, and all the variables
4(2x+5)+8
We multiply parentheses
8x+20+8
We add all the numbers together, and all the variables
8x+28
Back to the equation:
-(8x+28)
9x-(8x+28)+26=0
We get rid of parentheses
9x-8x-28+26=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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