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x-6/3x+1=x+2/x
We move all terms to the left:
x-6/3x+1-(x+2/x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-6/3x-(+x+2/x)+1=0
We get rid of parentheses
x-6/3x-x-2/x+1=0
We calculate fractions
x-x+(-6x)/3x^2+(-6x)/3x^2+1=0
We add all the numbers together, and all the variables
(-6x)/3x^2+(-6x)/3x^2+1=0
We multiply all the terms by the denominator
(-6x)+(-6x)+1*3x^2=0
Wy multiply elements
3x^2+(-6x)+(-6x)=0
We get rid of parentheses
3x^2-6x-6x=0
We add all the numbers together, and all the variables
3x^2-12x=0
a = 3; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·3·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*3}=\frac{24}{6} =4 $
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