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5(x+8)=2x-7+8(x+1)
We move all terms to the left:
5(x+8)-(2x-7+8(x+1))=0
We multiply parentheses
5x-(2x-7+8(x+1))+40=0
We calculate terms in parentheses: -(2x-7+8(x+1)), so:We get rid of parentheses
2x-7+8(x+1)
determiningTheFunctionDomain 2x+8(x+1)-7
We multiply parentheses
2x+8x+8-7
We add all the numbers together, and all the variables
10x+1
Back to the equation:
-(10x+1)
5x-10x-1+40=0
We add all the numbers together, and all the variables
-5x+39=0
We move all terms containing x to the left, all other terms to the right
-5x=-39
x=-39/-5
x=7+4/5
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