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x-5=x(x+3)
We move all terms to the left:
x-5-(x(x+3))=0
We calculate terms in parentheses: -(x(x+3)), so:We get rid of parentheses
x(x+3)
We multiply parentheses
x^2+3x
Back to the equation:
-(x^2+3x)
-x^2+x-3x-5=0
We add all the numbers together, and all the variables
-1x^2-2x-5=0
a = -1; b = -2; c = -5;
Δ = b2-4ac
Δ = -22-4·(-1)·(-5)
Δ = -16
Delta is less than zero, so there is no solution for the equation
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