4(5x+2)=10(3x-3)+15

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Solution for 4(5x+2)=10(3x-3)+15 equation: 



4(5x+2)=10(3x-3)+15

We move all terms to the left:

4(5x+2)-(10(3x-3)+15)=0

We multiply parentheses

20x-(10(3x-3)+15)+8=0



We calculate terms in parentheses: -(10(3x-3)+15), so:

10(3x-3)+15

We multiply parentheses

30x-30+15

We add all the numbers together, and all the variables

30x-15

Back to the equation:

-(30x-15)



We get rid of parentheses

20x-30x+15+8=0

We add all the numbers together, and all the variables

-10x+23=0

We move all terms containing x to the left, all other terms to the right

-10x=-23

x=-23/-10

x=2+3/10

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