x-4/(x-2)(x-3)=0

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Solution for x-4/(x-2)(x-3)=0 equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

x-((4/(x-2))*(x-3)) = 0

x-4*(x-2)^-1*(x-3) = 0

(-4*(x-3))/(x-2)+x = 0

(-4*(x-3))/(x-2)+(x*(x-2))/(x-2) = 0

x*(x-2)-4*(x-3) = 0

x^2-6*x+12 = 0

x^2-6*x+12 = 0

x^2-6*x+12 = 0

DELTA = (-6)^2-(1*4*12)

DELTA = -12

DELTA < 0

1 = 0

1/(x-2) = 0

1/(x-2) = 0 // * x-2

1 = 0

x belongs to the empty set

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