Cosx(1-2sinx)=0

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Solution for Cosx(1-2sinx)=0 equation: 


Simplifying
Cosx(1 + -2sinx) = 0
(1 * osxC + -2insx * osxC) = 0

Reorder the terms:
(-2inos2x2C + 1osxC) = 0
(-2inos2x2C + 1osxC) = 0

Solving
-2inos2x2C + 1osxC = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1osxC' to each side of the equation.
-2inos2x2C + 1osxC + -1osxC = 0 + -1osxC

Combine like terms: 1osxC + -1osxC = 0
-2inos2x2C + 0 = 0 + -1osxC
-2inos2x2C = 0 + -1osxC
Remove the zero:
-2inos2x2C = -1osxC

Divide each side by '-2nos2x2C'.
i = 0.5n-1s-1x-1

Simplifying
i = 0.5n-1s-1x-1

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