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x-3=5(2x+5)
We move all terms to the left:
x-3-(5(2x+5))=0
We calculate terms in parentheses: -(5(2x+5)), so:We get rid of parentheses
5(2x+5)
We multiply parentheses
10x+25
Back to the equation:
-(10x+25)
x-10x-25-3=0
We add all the numbers together, and all the variables
-9x-28=0
We move all terms containing x to the left, all other terms to the right
-9x=28
x=28/-9
x=-3+1/9
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