20-2(z-5)=(10-3z)

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Solution for 20-2(z-5)=(10-3z) equation: 



20-2(z-5)=(10-3z)

We move all terms to the left:

20-2(z-5)-((10-3z))=0

We add all the numbers together, and all the variables

-2(z-5)-((-3z+10))+20=0

We multiply parentheses

-2z-((-3z+10))+10+20=0



We calculate terms in parentheses: -((-3z+10)), so:

(-3z+10)

We get rid of parentheses

-3z+10

Back to the equation:

-(-3z+10)



We add all the numbers together, and all the variables

-2z-(-3z+10)+30=0

We get rid of parentheses

-2z+3z-10+30=0

We add all the numbers together, and all the variables

z+20=0

We move all terms containing z to the left, all other terms to the right

z=-20

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