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x-3=105/3x-3
We move all terms to the left:
x-3-(105/3x-3)=0
Domain of the equation: 3x-3)!=0We get rid of parentheses
x∈R
x-105/3x+3-3=0
We multiply all the terms by the denominator
x*3x+3*3x-3*3x-105=0
Wy multiply elements
3x^2+9x-9x-105=0
We add all the numbers together, and all the variables
3x^2-105=0
a = 3; b = 0; c = -105;
Δ = b2-4ac
Δ = 02-4·3·(-105)
Δ = 1260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1260}=\sqrt{36*35}=\sqrt{36}*\sqrt{35}=6\sqrt{35}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{35}}{2*3}=\frac{0-6\sqrt{35}}{6} =-\frac{6\sqrt{35}}{6} =-\sqrt{35} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{35}}{2*3}=\frac{0+6\sqrt{35}}{6} =\frac{6\sqrt{35}}{6} =\sqrt{35} $
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