4a+7(2a-5)-5(3a+11)=50

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Solution for 4a+7(2a-5)-5(3a+11)=50 equation: 



4a+7(2a-5)-5(3a+11)=50

We move all terms to the left:

4a+7(2a-5)-5(3a+11)-(50)=0

We multiply parentheses

4a+14a-15a-35-55-50=0

We add all the numbers together, and all the variables

3a-140=0

We move all terms containing a to the left, all other terms to the right

3a=140

a=140/3

a=46+2/3

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