x-3(6+x)=x-2(4+x)

Solution for x-3(6+x)=x-2(4+x) equation:

x-3(6+x)=x-2(4+x)

We move all terms to the left:

x-3(6+x)-(x-2(4+x))=0

We add all the numbers together, and all the variables

x-3(x+6)-(x-2(x+4))=0

We multiply parentheses

x-3x-(x-2(x+4))-18=0


We calculate terms in parentheses: -(x-2(x+4)), so:

x-2(x+4)

We multiply parentheses

x-2x-8

We add all the numbers together, and all the variables

-1x-8

Back to the equation:

-(-1x-8)


We add all the numbers together, and all the variables

-2x-(-1x-8)-18=0

We get rid of parentheses

-2x+1x+8-18=0

We add all the numbers together, and all the variables

-1x-10=0

We move all terms containing x to the left, all other terms to the right

-x=10

x=10/-1

x=-10