(7x-4)=(5x+20)

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Solution for (7x-4)=(5x+20) equation: 



(7x-4)=(5x+20)

We move all terms to the left:

(7x-4)-((5x+20))=0

We get rid of parentheses

7x-((5x+20))-4=0



We calculate terms in parentheses: -((5x+20)), so:

(5x+20)

We get rid of parentheses

5x+20

Back to the equation:

-(5x+20)



We get rid of parentheses

7x-5x-20-4=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12

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