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x-27/4x=23
We move all terms to the left:
x-27/4x-(23)=0
Domain of the equation: 4x!=0We multiply all the terms by the denominator
x!=0/4
x!=0
x∈R
x*4x-23*4x-27=0
Wy multiply elements
4x^2-92x-27=0
a = 4; b = -92; c = -27;
Δ = b2-4ac
Δ = -922-4·4·(-27)
Δ = 8896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8896}=\sqrt{64*139}=\sqrt{64}*\sqrt{139}=8\sqrt{139}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-8\sqrt{139}}{2*4}=\frac{92-8\sqrt{139}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+8\sqrt{139}}{2*4}=\frac{92+8\sqrt{139}}{8} $
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