x(8x-4)=(8x+6)(x-5)

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Solution for x(8x-4)=(8x+6)(x-5) equation: 



x(8x-4)=(8x+6)(x-5)

We move all terms to the left:

x(8x-4)-((8x+6)(x-5))=0

We multiply parentheses

8x^2-4x-((8x+6)(x-5))=0

We multiply parentheses ..

8x^2-((+8x^2-40x+6x-30))-4x=0



We calculate terms in parentheses: -((+8x^2-40x+6x-30)), so:

(+8x^2-40x+6x-30)

We get rid of parentheses

8x^2-40x+6x-30

We add all the numbers together, and all the variables

8x^2-34x-30

Back to the equation:

-(8x^2-34x-30)



We add all the numbers together, and all the variables

8x^2-4x-(8x^2-34x-30)=0

We get rid of parentheses

8x^2-8x^2-4x+34x+30=0

We add all the numbers together, and all the variables

30x+30=0

We move all terms containing x to the left, all other terms to the right

30x=-30

x=-30/30

x=-1

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