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x-2/7x=5
We move all terms to the left:
x-2/7x-(5)=0
Domain of the equation: 7x!=0We multiply all the terms by the denominator
x!=0/7
x!=0
x∈R
x*7x-5*7x-2=0
Wy multiply elements
7x^2-35x-2=0
a = 7; b = -35; c = -2;
Δ = b2-4ac
Δ = -352-4·7·(-2)
Δ = 1281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1281}}{2*7}=\frac{35-\sqrt{1281}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1281}}{2*7}=\frac{35+\sqrt{1281}}{14} $
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