1/5(5x-20)=1/2(2x+10)

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Solution for 1/5(5x-20)=1/2(2x+10) equation: 



1/5(5x-20)=1/2(2x+10)

We move all terms to the left:

1/5(5x-20)-(1/2(2x+10))=0



Domain of the equation: 5(5x-20)!=0

x∈R





Domain of the equation: 2(2x+10))!=0

x∈R



We calculate fractions


(2x2/(5(5x-20)*2(2x+10)))+(-5x5/(5(5x-20)*2(2x+10)))=0



We calculate terms in parentheses: +(2x2/(5(5x-20)*2(2x+10))), so:

2x2/(5(5x-20)*2(2x+10))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)





We calculate terms in parentheses: +(-5x5/(5(5x-20)*2(2x+10))), so:

-5x5/(5(5x-20)*2(2x+10))

We multiply all the terms by the denominator


-5x5

We add all the numbers together, and all the variables

-5x^5

We do not support expression: x^5

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