-(7r+3)=3(7-5r)+5r

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Solution for -(7r+3)=3(7-5r)+5r equation: 



-(7r+3)=3(7-5r)+5r

We move all terms to the left:

-(7r+3)-(3(7-5r)+5r)=0

We add all the numbers together, and all the variables

-(7r+3)-(3(-5r+7)+5r)=0

We get rid of parentheses

-7r-(3(-5r+7)+5r)-3=0



We calculate terms in parentheses: -(3(-5r+7)+5r), so:

3(-5r+7)+5r

We add all the numbers together, and all the variables

5r+3(-5r+7)

We multiply parentheses

5r-15r+21

We add all the numbers together, and all the variables

-10r+21

Back to the equation:

-(-10r+21)



We get rid of parentheses

-7r+10r-21-3=0

We add all the numbers together, and all the variables

3r-24=0

We move all terms containing r to the left, all other terms to the right

3r=24

r=24/3

r=8

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