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x-2/5x=42
We move all terms to the left:
x-2/5x-(42)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
x*5x-42*5x-2=0
Wy multiply elements
5x^2-210x-2=0
a = 5; b = -210; c = -2;
Δ = b2-4ac
Δ = -2102-4·5·(-2)
Δ = 44140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{44140}=\sqrt{4*11035}=\sqrt{4}*\sqrt{11035}=2\sqrt{11035}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-210)-2\sqrt{11035}}{2*5}=\frac{210-2\sqrt{11035}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-210)+2\sqrt{11035}}{2*5}=\frac{210+2\sqrt{11035}}{10} $
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