4y-5=2(3y-1)

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Solution for 4y-5=2(3y-1) equation: 



4y-5=2(3y-1)

We move all terms to the left:

4y-5-(2(3y-1))=0



We calculate terms in parentheses: -(2(3y-1)), so:

2(3y-1)

We multiply parentheses

6y-2

Back to the equation:

-(6y-2)



We get rid of parentheses

4y-6y+2-5=0

We add all the numbers together, and all the variables

-2y-3=0

We move all terms containing y to the left, all other terms to the right

-2y=3

y=3/-2

y=-1+1/2

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