0=7X2+16x-48

Solution for 0=7X2+16x-48 equation:

0=7X^2+16X-48

We move all terms to the left:

0-(7X^2+16X-48)=0

We add all the numbers together, and all the variables

-(7X^2+16X-48)=0

We get rid of parentheses

-7X^2-16X+48=0

a = -7; b = -16; c = +48;
Δ = b2-4ac
Δ = -162-4·(-7)·48
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-40}{2*-7}=\frac{-24}{-14}
=1+5/7
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+40}{2*-7}=\frac{56}{-14}
=-4
$