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x-2-2x+4=3(2x-3)
We move all terms to the left:
x-2-2x+4-(3(2x-3))=0
We add all the numbers together, and all the variables
-1x-(3(2x-3))+2=0
We calculate terms in parentheses: -(3(2x-3)), so:We get rid of parentheses
3(2x-3)
We multiply parentheses
6x-9
Back to the equation:
-(6x-9)
-1x-6x+9+2=0
We add all the numbers together, and all the variables
-7x+11=0
We move all terms containing x to the left, all other terms to the right
-7x=-11
x=-11/-7
x=1+4/7
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