6(2v+4)=-8(v-4)

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Solution for 6(2v+4)=-8(v-4) equation: 



6(2v+4)=-8(v-4)

We move all terms to the left:

6(2v+4)-(-8(v-4))=0

We multiply parentheses

12v-(-8(v-4))+24=0



We calculate terms in parentheses: -(-8(v-4)), so:

-8(v-4)

We multiply parentheses

-8v+32

Back to the equation:

-(-8v+32)



We get rid of parentheses

12v+8v-32+24=0

We add all the numbers together, and all the variables

20v-8=0

We move all terms containing v to the left, all other terms to the right

20v=8

v=8/20

v=2/5

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