x-2*(x-3)-10=-6-3*(x+2)

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Solution for x-2*(x-3)-10=-6-3*(x+2) equation: 



x-2(x-3)-10=-6-3(x+2)

We move all terms to the left:

x-2(x-3)-10-(-6-3(x+2))=0

We multiply parentheses

x-2x-(-6-3(x+2))+6-10=0



We calculate terms in parentheses: -(-6-3(x+2)), so:

-6-3(x+2)

determiningTheFunctionDomain
-3(x+2)-6

We multiply parentheses

-3x-6-6

We add all the numbers together, and all the variables

-3x-12

Back to the equation:

-(-3x-12)



We add all the numbers together, and all the variables

-1x-(-3x-12)-4=0

We get rid of parentheses

-1x+3x+12-4=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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