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x=3x-3/6x+5
We move all terms to the left:
x-(3x-3/6x+5)=0
Domain of the equation: 6x+5)!=0We get rid of parentheses
x∈R
x-3x+3/6x-5=0
We multiply all the terms by the denominator
x*6x-3x*6x-5*6x+3=0
Wy multiply elements
6x^2-18x^2-30x+3=0
We add all the numbers together, and all the variables
-12x^2-30x+3=0
a = -12; b = -30; c = +3;
Δ = b2-4ac
Δ = -302-4·(-12)·3
Δ = 1044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1044}=\sqrt{36*29}=\sqrt{36}*\sqrt{29}=6\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6\sqrt{29}}{2*-12}=\frac{30-6\sqrt{29}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6\sqrt{29}}{2*-12}=\frac{30+6\sqrt{29}}{-24} $
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