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x-1=-5x+2/2x
We move all terms to the left:
x-1-(-5x+2/2x)=0
Domain of the equation: 2x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
x+5x-2/2x-1=0
We multiply all the terms by the denominator
x*2x+5x*2x-1*2x-2=0
Wy multiply elements
2x^2+10x^2-2x-2=0
We add all the numbers together, and all the variables
12x^2-2x-2=0
a = 12; b = -2; c = -2;
Δ = b2-4ac
Δ = -22-4·12·(-2)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*12}=\frac{-8}{24} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*12}=\frac{12}{24} =1/2 $
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