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x-2/5x-40-2/5x=60
We move all terms to the left:
x-2/5x-40-2/5x-(60)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
x-2/5x-2/5x-100=0
We multiply all the terms by the denominator
x*5x-100*5x-2-2=0
We add all the numbers together, and all the variables
x*5x-100*5x-4=0
Wy multiply elements
5x^2-500x-4=0
a = 5; b = -500; c = -4;
Δ = b2-4ac
Δ = -5002-4·5·(-4)
Δ = 250080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{250080}=\sqrt{16*15630}=\sqrt{16}*\sqrt{15630}=4\sqrt{15630}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-500)-4\sqrt{15630}}{2*5}=\frac{500-4\sqrt{15630}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-500)+4\sqrt{15630}}{2*5}=\frac{500+4\sqrt{15630}}{10} $
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