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x-12=x-2(3-2x)
We move all terms to the left:
x-12-(x-2(3-2x))=0
We add all the numbers together, and all the variables
x-(x-2(-2x+3))-12=0
We calculate terms in parentheses: -(x-2(-2x+3)), so:We get rid of parentheses
x-2(-2x+3)
We multiply parentheses
x+4x-6
We add all the numbers together, and all the variables
5x-6
Back to the equation:
-(5x-6)
x-5x+6-12=0
We add all the numbers together, and all the variables
-4x-6=0
We move all terms containing x to the left, all other terms to the right
-4x=6
x=6/-4
x=-1+1/2
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