(72/x)+3=72/(x-4)

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Solution for (72/x)+3=72/(x-4) equation: 



(72/x)+3=72/(x-4)

We move all terms to the left:

(72/x)+3-(72/(x-4))=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: (x-4))!=0

x∈R



We add all the numbers together, and all the variables

(+72/x)-(72/(x-4))+3=0

We get rid of parentheses

72/x-(72/(x-4))+3=0

We calculate fractions


72x/(-3x^2)+(-(72*x)/(-3x^2)+3=0

We add all the numbers together, and all the variables

72x/(-3x^2)+(-(+72x)/(-3x^2)+3=0

We calculate fractions

We do not support expression: x^3

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