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x-1/5x=8
We move all terms to the left:
x-1/5x-(8)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
x*5x-8*5x-1=0
Wy multiply elements
5x^2-40x-1=0
a = 5; b = -40; c = -1;
Δ = b2-4ac
Δ = -402-4·5·(-1)
Δ = 1620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1620}=\sqrt{324*5}=\sqrt{324}*\sqrt{5}=18\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-18\sqrt{5}}{2*5}=\frac{40-18\sqrt{5}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+18\sqrt{5}}{2*5}=\frac{40+18\sqrt{5}}{10} $
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