15(x+3)=5(x-11)+20

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Solution for 15(x+3)=5(x-11)+20 equation: 



15(x+3)=5(x-11)+20

We move all terms to the left:

15(x+3)-(5(x-11)+20)=0

We multiply parentheses

15x-(5(x-11)+20)+45=0



We calculate terms in parentheses: -(5(x-11)+20), so:

5(x-11)+20

We multiply parentheses

5x-55+20

We add all the numbers together, and all the variables

5x-35

Back to the equation:

-(5x-35)



We get rid of parentheses

15x-5x+35+45=0

We add all the numbers together, and all the variables

10x+80=0

We move all terms containing x to the left, all other terms to the right

10x=-80

x=-80/10

x=-8

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