x+x+1/6x=16

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Solution for x+x+1/6x=16 equation:



x+x+1/6x=16
We move all terms to the left:
x+x+1/6x-(16)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
We add all the numbers together, and all the variables
2x+1/6x-16=0
We multiply all the terms by the denominator
2x*6x-16*6x+1=0
Wy multiply elements
12x^2-96x+1=0
a = 12; b = -96; c = +1;
Δ = b2-4ac
Δ = -962-4·12·1
Δ = 9168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{9168}=\sqrt{16*573}=\sqrt{16}*\sqrt{573}=4\sqrt{573}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-4\sqrt{573}}{2*12}=\frac{96-4\sqrt{573}}{24} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+4\sqrt{573}}{2*12}=\frac{96+4\sqrt{573}}{24} $

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