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3(x-1)+4=2(2x+1)-x
We move all terms to the left:
3(x-1)+4-(2(2x+1)-x)=0
We multiply parentheses
3x-(2(2x+1)-x)-3+4=0
We calculate terms in parentheses: -(2(2x+1)-x), so:We add all the numbers together, and all the variables
2(2x+1)-x
We add all the numbers together, and all the variables
-1x+2(2x+1)
We multiply parentheses
-1x+4x+2
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
3x-(3x+2)+1=0
We get rid of parentheses
3x-3x-2+1=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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