x+5/4x=288+1/5x

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Solution for x+5/4x=288+1/5x equation:



x+5/4x=288+1/5x
We move all terms to the left:
x+5/4x-(288+1/5x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
x+5/4x-(1/5x+288)=0
We get rid of parentheses
x+5/4x-1/5x-288=0
We calculate fractions
x+25x/20x^2+(-4x)/20x^2-288=0
We multiply all the terms by the denominator
x*20x^2+25x+(-4x)-288*20x^2=0
We add all the numbers together, and all the variables
25x+x*20x^2+(-4x)-288*20x^2=0
Wy multiply elements
20x^3-5760x^2+25x+(-4x)=0
We get rid of parentheses
20x^3-5760x^2+25x-4x=0
We do not support expression: x^3

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