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182=3x+11/5x
We move all terms to the left:
182-(3x+11/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+3x+11/5x)+182=0
We get rid of parentheses
-3x-11/5x+182=0
We multiply all the terms by the denominator
-3x*5x+182*5x-11=0
Wy multiply elements
-15x^2+910x-11=0
a = -15; b = 910; c = -11;
Δ = b2-4ac
Δ = 9102-4·(-15)·(-11)
Δ = 827440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{827440}=\sqrt{16*51715}=\sqrt{16}*\sqrt{51715}=4\sqrt{51715}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(910)-4\sqrt{51715}}{2*-15}=\frac{-910-4\sqrt{51715}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(910)+4\sqrt{51715}}{2*-15}=\frac{-910+4\sqrt{51715}}{-30} $
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