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x+4=(x+2)
We move all terms to the left:
x+4-((x+2))=0
We calculate terms in parentheses: -((x+2)), so:We get rid of parentheses
(x+2)
We get rid of parentheses
x+2
Back to the equation:
-(x+2)
x-x-2+4=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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