x+4-3(x-2)=16-5x

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Solution for x+4-3(x-2)=16-5x equation:



x+4-3(x-2)=16-5x
We move all terms to the left:
x+4-3(x-2)-(16-5x)=0
We add all the numbers together, and all the variables
x-3(x-2)-(-5x+16)+4=0
We multiply parentheses
x-3x-(-5x+16)+6+4=0
We get rid of parentheses
x-3x+5x-16+6+4=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2

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