2(n+0.6)+2n=2(n+0.1)+2(2n)

Solution for 2(n+0.6)+2n=2(n+0.1)+2(2n) equation:

2(n+0.6)+2n=2(n+0.1)+2(2n)

We move all terms to the left:

2(n+0.6)+2n-(2(n+0.1)+2(2n))=0

We add all the numbers together, and all the variables

2n+2(n+0.6)-(2(n+0.1)+22n)=0

We multiply parentheses

2n+2n-(2(n+0.1)+22n)+1.2=0


We calculate terms in parentheses: -(2(n+0.1)+22n), so:

2(n+0.1)+22n

We add all the numbers together, and all the variables

22n+2(n+0.1)

We multiply parentheses

22n+2n+0.2

We add all the numbers together, and all the variables

24n+0.2

Back to the equation:

-(24n+0.2)


We add all the numbers together, and all the variables

4n-(24n+0.2)+1.2=0

We get rid of parentheses

4n-24n-0.2+1.2=0

We add all the numbers together, and all the variables

-20n+1=0

We move all terms containing n to the left, all other terms to the right

-20n=-1

n=-1/-20

n=1/20