x+3/2+3x=5(x-3)+(x+23)/5

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Solution for x+3/2+3x=5(x-3)+(x+23)/5 equation: 



x+3/2+3x=5(x-3)+(x+23)/5

We move all terms to the left:

x+3/2+3x-(5(x-3)+(x+23)/5)=0

We add all the numbers together, and all the variables

4x-(5(x-3)+(x+23)/5)+3/2=0

We calculate fractions


4x+(-(5(x-3)+(x+23)*2)/()+()/()=0



We calculate terms in parentheses: +(-(5(x-3)+(x+23)*2)/()+()/(), so:

-(5(x-3)+(x+23)*2)/()+()/(

We add all the numbers together, and all the variables

-(5(x-3)+(x+23)*2)/()+1

We multiply all the terms by the denominator


-(5(x-3)+(x+23)*2)+1*()



We calculate terms in parentheses: -(5(x-3)+(x+23)*2), so:

5(x-3)+(x+23)*2

We multiply parentheses

5x+2x-15+46

We add all the numbers together, and all the variables

7x+31

Back to the equation:

-(7x+31)



We add all the numbers together, and all the variables

-(7x+31)

We get rid of parentheses

-7x-31

Back to the equation:

+(-7x-31)



We get rid of parentheses

4x-7x-31=0

We add all the numbers together, and all the variables

-3x-31=0

We move all terms containing x to the left, all other terms to the right

-3x=31

x=31/-3

x=-10+1/3

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