5(3x+11)=10(2x-1)

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Solution for 5(3x+11)=10(2x-1) equation:



5(3x+11)=10(2x-1)
We move all terms to the left:
5(3x+11)-(10(2x-1))=0
We multiply parentheses
15x-(10(2x-1))+55=0
We calculate terms in parentheses: -(10(2x-1)), so:
10(2x-1)
We multiply parentheses
20x-10
Back to the equation:
-(20x-10)
We get rid of parentheses
15x-20x+10+55=0
We add all the numbers together, and all the variables
-5x+65=0
We move all terms containing x to the left, all other terms to the right
-5x=-65
x=-65/-5
x=+13

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