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x+2x+6=2(x+3)+2
We move all terms to the left:
x+2x+6-(2(x+3)+2)=0
We add all the numbers together, and all the variables
3x-(2(x+3)+2)+6=0
We calculate terms in parentheses: -(2(x+3)+2), so:We get rid of parentheses
2(x+3)+2
We multiply parentheses
2x+6+2
We add all the numbers together, and all the variables
2x+8
Back to the equation:
-(2x+8)
3x-2x-8+6=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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