I((3x-4)/(8x+7))I=6

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Solution for I((3x-4)/(8x+7))I=6 equation: 



((3I-4)/(8I+7))=6

We move all terms to the left:

((3I-4)/(8I+7))-(6)=0



Domain of the equation: (8I+7))!=0

I∈R



We multiply all the terms by the denominator


((3I-4)-6*(8I+7))=0



We calculate terms in parentheses: +((3I-4)-6*(8I+7)), so:

(3I-4)-6*(8I+7)

We multiply parentheses

(3I-4)-48I-42

We get rid of parentheses

3I-48I-4-42

We add all the numbers together, and all the variables

-45I-46

Back to the equation:

+(-45I-46)



We get rid of parentheses

-45I-46=0

We move all terms containing I to the left, all other terms to the right

-45I=46

I=46/-45

I=-1+1/45

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