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x+2=7/8x-15.x
We move all terms to the left:
x+2-(7/8x-15.x)=0
Domain of the equation: 8x-15.x)!=0We add all the numbers together, and all the variables
x∈R
x-(-15x+7/8x)+2=0
We get rid of parentheses
x+15x-7/8x+2=0
We multiply all the terms by the denominator
x*8x+15x*8x+2*8x-7=0
Wy multiply elements
8x^2+120x^2+16x-7=0
We add all the numbers together, and all the variables
128x^2+16x-7=0
a = 128; b = 16; c = -7;
Δ = b2-4ac
Δ = 162-4·128·(-7)
Δ = 3840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3840}=\sqrt{256*15}=\sqrt{256}*\sqrt{15}=16\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16\sqrt{15}}{2*128}=\frac{-16-16\sqrt{15}}{256} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16\sqrt{15}}{2*128}=\frac{-16+16\sqrt{15}}{256} $
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