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3(2x-4)+2(2x-3)=4(2x-3)
We move all terms to the left:
3(2x-4)+2(2x-3)-(4(2x-3))=0
We multiply parentheses
6x+4x-(4(2x-3))-12-6=0
We calculate terms in parentheses: -(4(2x-3)), so:We add all the numbers together, and all the variables
4(2x-3)
We multiply parentheses
8x-12
Back to the equation:
-(8x-12)
10x-(8x-12)-18=0
We get rid of parentheses
10x-8x+12-18=0
We add all the numbers together, and all the variables
2x-6=0
We move all terms containing x to the left, all other terms to the right
2x=6
x=6/2
x=3
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