x+240/15=(1/3)x

Solution for x+240/15=(1/3)x equation:

x+240/15=(1/3)x

We move all terms to the left:

x+240/15-((1/3)x)=0


Domain of the equation: 3)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-((+1/3)x)+240/15=0

We add all the numbers together, and all the variables

x-((+1/3)x)+16=0

We multiply all the terms by the denominator


x*3)x)-((+16*3)x)+1=0

We add all the numbers together, and all the variables

x*3)x)-(48x)+1=0

We add all the numbers together, and all the variables

x*3)x)-48x+1=0

Wy multiply elements

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$